golang json解析太蠢，scala json處理入門

2023-12-06 阅读 16 评论 0

摘要：依賴 <dependency><groupId>com.alibaba</groupId><artifactId>fastjson</artifactId><version>1.2.47</version> </dependency> 構建json對象 def test1(): Unit ={val nObject = new JSONObject()nObject.put("

依賴

<dependency><groupId>com.alibaba</groupId><artifactId>fastjson</artifactId><version>1.2.47</version>
</dependency>

構建json對象

def test1(): Unit ={val nObject = new JSONObject()nObject.put("name","xiaoming")nObject.put("age",23)println(nObject)//{"name":"xiaoming","age":23}
}

json字符串轉json對象

def decode(): Unit = {val str = "{'name':'xiaoming','age':23}"val nObject: JSONObject = JSON.parseObject(str)val str1: String = nObject.getString("name")println(s"str1 = ${str1}")//str1 = xiaoming}

Json對象轉字符串

 def json2str(): Unit = {val str = "{'name':'xiaoming','age':23}"val nObject: JSONObject = JSON.parseObject(str)val string: String = nObject.toJSONStringprintln(s"string = ${string}")//string = {"name":"xiaoming","age":23}}

提取json字符串中數組的部分信息

 def getarray(): Unit ={import com.alibaba.fastjson.JSONArrayimport com.alibaba.fastjson.JSONObjectval str: String = "{\n" + "'name':'網站',\n" + "'num':3,\n" + "'sites':[ 'Google', 'Runoob', 'Taobao' ]\n" + "}"//字符串轉json對象val jsonObject: JSONObject = JSON.parseObject(str)//將JSON對象轉化為字符串val sites: String = jsonObject.getString("sites")//提取字符串中的數組val array: JSONArray = JSON.parseArray(sites)//獲取數組的第一個元素System.out.println(array.get(0)) //Google}