杭電oj2017,杭電1963 完全背包

 2023-10-07 阅读 20 评论 0

摘要:完全背包,但是總容量不穩定,隨著每年的盈利,背包容量在變大,而且,題目給的數據比較大,但是給的有投資的都是1000 的倍數,運用的時候除以1000即可,附代碼: Time Limit : 5000/1000ms (Java/Other)???Memory L


完全背包,但是總容量不穩定,隨著每年的盈利,背包容量在變大,而且,題目給的數據比較大,但是給的有投資的都是1000 的倍數,運用的時候除以1000即可,附代碼:

Time Limit : 5000/1000ms (Java/Other)???Memory Limit : 65536/32768K (Java/Other)
Total Submission(s) : 2???Accepted Submission(s) : 1
Problem Description
John never knew he had a grand-uncle, until he received the notary’s letter. He learned that his late grand-uncle had gathered a lot of money, somewhere in South-America, and that John was the only inheritor.

John did not need that much money for the moment. But he realized that it would be a good idea to store this capital in a safe place, and have it grow until he decided to retire. The bank convinced him that a certain kind of bond was interesting for him.?

This kind of bond has a fixed value, and gives a fixed amount of yearly interest, payed to the owner at the end of each year. The bond has no fixed term. Bonds are available in different sizes. The larger ones usually give a better interest. Soon John realized that the optimal set of bonds to buy was not trivial to figure out. Moreover, after a few years his capital would have grown, and the schedule had to be re-evaluated.

Assume the following bonds are available:
Value Annual interest
4000 ??400
3000 ??250

With a capital of $10 000 one could buy two bonds of $4 000, giving a yearly interest of $800. Buying two bonds of $3 000, and one of $4 000 is a better idea, as it gives a yearly interest of $900. After two years the capital has grown to $11 800, and it makes sense to sell a $3 000 one and buy a $4 000 one, so the annual interest grows to $1 050. This is where this story grows unlikely: the bank does not charge for buying and selling bonds. Next year the total sum is $12 850, which allows for three times $4 000, giving a yearly interest of $1 200.?

Here is your problem: given an amount to begin with, a number of years, and a set of bonds with their values and interests, find out how big the amount may grow in the given period, using the best schedule for buying and selling bonds.

Input
The first line contains a single positive integer N which is the number of test cases. The test cases follow. The first line of a test case contains two positive integers: the amount to start with (at most $1 000 000), and the number of years the capital may grow (at most 40). The following line contains a single number: the number d (1 <= d <= 10) of available bonds. The next d lines each contain the description of a bond. The description of a bond consists of two positive integers: the value of the bond, and the yearly interest for that bond. The value of a bond is always a multiple of $1 000. The interest of a bond is never more than 10% of its value.

Output
For each test case, output – on a separate line – the capital at the end of the period, after an optimal schedule of buying and selling.

Sample Input
1 10000 4 2 4000 400 3000 250

Sample Output
14050

Source
NWERC2004

附代碼:
#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;
int cost[1100000],ans[1100000],i,j,k,l,m,n,gett[1100000];
int main()
{int p;scanf("%d",&p);while(p--){scanf("%d%d",&n,&m);scanf("%d",&k);for(i=1;i<=k;i++)scanf("%d%d",&cost[i],&gett[i]);memset(ans,0,sizeof(ans));int help=n;for(int x=0;x<m;x++){for(i=1;i<=k;i++){for(j=cost[i]/1000;j<=help/1000;j++)ans[j]=max(ans[j],ans[j-cost[i]/1000]+gett[i]);	}help+=ans[j-1];}printf("%d\n",help);}
}


版权声明:本站所有资料均为网友推荐收集整理而来,仅供学习和研究交流使用。

原文链接:https://hbdhgg.com/3/128138.html

发表评论:

本站为非赢利网站,部分文章来源或改编自互联网及其他公众平台,主要目的在于分享信息,版权归原作者所有,内容仅供读者参考,如有侵权请联系我们删除!

Copyright © 2022 匯編語言學習筆記 Inc. 保留所有权利。

底部版权信息