html文件怎么保存链接,如何使用beautifulsoup将链接的html保存在文件中，并对html文件中的所有链接执行相同的操作...

我明白了。 使用美丽的汤递归URL解析的代码：

import requests

import urllib2

怎么将网页以html保存到文件夹中。from bs4 import BeautifulSoup

link_set = set()

give_url = raw_input("Enter url:\t")

def magic(give_url, link_set, count):

html文件怎么打开？# print "______________________________________________________"

#

# print "Count is: " + str(count)

# count += 1

html保存，# print "THE URL IT IS SCRAPPING IS:" + give_url

page = urllib2.urlopen(give_url)

page_content = page.read()

with open('page_content.html', 'w') as fid:

html5？fid.write(page_content)

response = requests.get(give_url)

html_data = response.text

soup = BeautifulSoup(html_data)

html。list_items = soup.find_all('a')

for each_item in list_items:

html_link = each_item.get('href')

if(html_link is None):

beautifulsoup干嘛的。pass

else:

if(not (html_link.startswith('http') or html_link.startswith('https'))):

link_set.add(give_url + html_link)

beautifulsoup的作用、else:

link_set.add(html_link)

# print "Total links in the given url are: " + str(len(link_set))

magic(give_url,link_set,0)

link_set2 = set()

link_set3 = set()

for element in link_set:

link_set2.add(element)

count = 1

for element in link_set:

magic(element,link_set3,count)

count += 1

for each_item in link_set3:

link_set2.add(each_item)

link_set3.clear()

count = 1

print "Total links scraped are: " + str(len(link_set2))

for element in link_set2:

count +=1

print "Element number " + str(count) + "processing"

print element

print "\n"

有很多错误，所以我要求你们都请告诉我在哪里可以提高代码。