題目描述

源代碼

#include<iostream>
using namespace std;int yinz[3]={3,5,7};
bool isNum(long long n)
{for(int i=0;i<3;i++){while(n%yinz[i]==0){n/=yinz[i];} }return n==1;
}
int main()
{long long count=0;for(long long i=3;i<=59084709587505;i++){if(isNum(i)) count++;}cout<<count;return 0;
}

正確答案

1905